Page 310 - ATA YAYINCILIK 8. Sınıf Ben Korkmam Matematik Soru Bankası

CEVAP ANAHTARI

2 Sayfa: 147 - 148
2
a) (2x + 1) · (2x + 2) = 4x + 6x + 2 Kazanım Değerlendirme Testi - 21
2
b) (x + 4) · (x + 3) = x + 7x + 12 1. B 3. D 5. A 7. D 9. D 11. C
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c) (2x + 3) · (x + 3) = 2x + 9x + 9 2. B 4. C 6. C 8. A 10. B 12. A
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ç) (3x + 1) · (x + 1) = 3x + 4x + 1
Sayfa: 149 - 150
3 4 5 1
2
2
5x – 3x ▲ = 11 ■ = 6 x – 2x + 1 a) 5 · (a + 3) d) 7 · (4x –3)
Sayfa: 141 - 142 b) 4a · (3a + 2) e) 10 · (2x – x – 1)
2
Kazanım Değerlendirme Testi - 20 c) 5 · (3x + 4x + 1) f) 6 · (3x + 2x + 1)
2
3
2
1. A 3. C 5. C 7. B 9. D ç) 6x · (–5 + 4x)
2. B 4. A 6. D 8. A 10. B
2
Sayfa: 143 - 144 a) (x + 4) · (x + 4) d) (3x + 2) · (3x + 2)
1 b) (y – 3) · (y – 3) e) (x – 12) · (x – 12)
a) Ö c) D d) Ö c) (3x – 4) · (3x + 4) f) 16 · (y – 1) · (y – 1)
b) D ç) D e) Ö ç) (5y – 1) · (5y + 1)
2 3
a) (x – y) · (x + y) d) (3m – 5) · (3m + 5) a) (12x – 4) cm b) (28a + 8y) cm c) (24x + 12y) cm
b) (x – 2) · (x + 2) e) (4y – 7) · (4y + 7) 4
c) (x – 4) · (x + 4) f) (9a – 6b) · (9a + 6b) 12x + 6
ç) (2a – 1) · (2a + 1)
5
a) 18x + 4y + 16 c) 12a
3 b) 48m ç) 16x + 18z + 2y
2
2
a) x + 2xy + y 2 ı) x – 2xy + y 2 Sayfa: 151 - 152
2
2
b) x + 6x + 9 i) x – 4x + 4 Kazanım Değerlendirme Testi - 22
2
2
c) 4m + 4m + 1 j) 4m – 12m + 9
2
2
ç) 9n + 12n + 4 k) 9n – 24n + 16 1. C 3. D 5. A 7. D 9. C
6. B
8. B
4. B
2. A
2
2
d) 25a + 10a + 1 l) 25a – 70a + 49
2
2
e) 16b + 24b + 9 m) 4x – 4xy + y 2 Sayfa: 153 - 154
2
2
f) 4a + 12ab + 9b 2 n) 9a – 24ab + 16b 2 Konu Değerlendirme Testi - 14
2
2
g) 9x + 24xy + 16y 2 o) 25m – 20mn + 4n 2 1. B 3. C
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h) 36m + 60 mn + 25n 2 2. A 4. D
Sayfa: 145 - 146 Sayfa: 155 - 156
1 Konu Değerlendirme Testi - 15
2
2
2
2
a) (x + 1) = x + 2x + 1 ç) (3x + 1) = 9x + 6x + 1 1. C 3. A
2
2
2
2
b) (x + 2) = x + 4x + 4 d) (2x + 2) = 4x + 8x + 4 2. B 4. B
2
2
2
2
c) (2x + 1) = 4x + 4x + 1 e) (2x + 3) = 4x + 12x + 9 Sayfa: 157 - 160
2
2
2
a) a – 5 = (a – 5) · (a + 5) 3. Ünite Değerlendirme Testi 7. B 9. C
1. A
5. B
3. C
2
2
2
b) x – 4 · 2 = x – 16 = (x – 4) · (x + 4) 2. D 4. B 6. D 8. A
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c) 4b – 9 = (2b – 3) · (2b + 3)
25 m 2 49 n 2 1
ç) – = · (5m – 7n) · (5m + 7n)
2 2 2
3
2
2
3 · (2b) – 3 · a = 3 · (2b – a) · (2b + a)
4
2
2
a) (4k – 3t) = 16k – 24kt + 9t 2
2
2
b) (5a + 2b) = 25a + 20ab + 4b 2
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